Write four solutions for the following equation: $4y - 11 = 0$.

(N/A) The given equation is $4y - 11 = 0$,which can be written as $0x + 4y = 11$.
This is a linear equation in two variables $x$ and $y$.
Since the coefficient of $x$ is $0$,the value of $y$ will always be $\frac{11}{4}$ regardless of the value of $x$.
We can choose any four arbitrary values for $x$ to find the corresponding solutions.
Let $x = 0$,then $y = \frac{11}{4}$. Solution: $(0, 2.75)$.
Let $x = 1$,then $y = \frac{11}{4}$. Solution: $(1, 2.75)$.
Let $x = 2$,then $y = \frac{11}{4}$. Solution: $(2, 2.75)$.
Let $x = 3$,then $y = \frac{11}{4}$. Solution: $(3, 2.75)$.
Thus,four solutions are $(0, 2.75), (1, 2.75), (2, 2.75), (3, 2.75)$.